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5V0-93.22 Exam Simulator
  • Exam Code: 5V0-93.22
  • Exam Name: VMware Carbon Black Cloud Endpoint Standard Skills
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  • Q & A: 40 Questions and Answers
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NEW QUESTION: 1
Examine these statements and the result:
CREATE SEQUENCE customer_seq CACHE 10;
SELECT customer_seq. NEXTVAL FROM DUAL; NEXTVAL
1
Now examine this command:
ALTER SEQUENCE customer_soq <MISaiNG CLAUSE>;
What must replace missing clause for customer_seq. nfxtvai. to return 11?
A. INCREMENT BY 10
B. NOCACHE
C. START WITH 11
D. cycle 11
E. MINVALUE 11
Answer: E

NEW QUESTION: 2
The public key is used to perform the following: (Choose three.)
A. Encrypt messages
B. Perform key escrow
C. Validate the CRL
D. Decrypt messages
E. Validate the identity of an email sender
F. Perform key recovery
Answer: A,D,E
Explanation:
Explanation/Reference:
Explanation:
B: The sender uses the private key to create a digital signature. The message is, in effect, signed with the private key. The sender then sends the message to the receiver. The receiver uses the public key attached to the message to validate the digital signature. If the values match, the receiver knows the message is authentic.
C: The sender uses the public key to encrypt a message, and the receiver uses the private key to decrypt the message.
E: You encrypt data with the private key and decrypt with the public key, though the opposite is much more frequent.
Public-key cryptography, also known as asymmetric cryptography, is a class of cryptographic protocols based on algorithms that require two separate keys, one of which is secret (or private) and one of which is public. Although different, the two parts of this key pair are mathematically linked.

NEW QUESTION: 3
What is wrong about the description of the business VAP below?
A. Provide wireless terminal access
B. Each RF can be configured with only one
C. Establish MESH connection establishment
D. Each RF can be configured in multiples, and the number is not limited.
Answer: B,C,D

NEW QUESTION: 4
Welche der folgenden Verschlüsselungstechniken schützt BEST ein drahtloses Netzwerk vor einem Man-in-the-Middle-Angriff?
A. 128-Bit-WEP (Wired Equivalent Privacy)
B. Alphanumerische Service-Set-ID (SSID)
C. MAC-basierter Pre-Shared-Key (PSK)
D. Zufällig generierter Pre-Shared Key (PSKJ
Answer: D
Explanation:
Erläuterung:
Ein zufällig generiertes PSK ist stärker als ein MAC-basiertes PSK, da die MAC-Adresse eines Computers fest und häufig zugänglich ist. Es hat sich gezeigt, dass WEP eine sehr schwache Verschlüsselungstechnik ist und innerhalb von Minuten geknackt werden kann. Die SSID wird im Funknetz im Klartext übertragen.

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