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NEW QUESTION: 1
SAP SuccessFactors Learning offers the following launch methods:
There are 4 correct answers to this question.
Response:
A. Media Player
B. AICC
C. SCORM
D. Browser
E. Content Player
Answer: B,C,D,E

NEW QUESTION: 2
Dell EMC Unityストレージ管理者は、SPとNASリソース間のフェイルオーバーをサポートするNASサーバー構成を構築する必要があります。この構成の用語は何ですか？
A. IP Multi-tenancy
B. Local Replication
C. Separate IP Switches
D. LACP
Answer: B
Explanation:
Reference:
https://www.delltechnologies.com/en-ae/documentation/unity-family/unity-p-replication-config/02- unity-rep-br-workflow.htm

NEW QUESTION: 3
会社には、プライベートサブネットのAmazonEC2インスタンスで実行されている複数のWebアプリケーションがあります。
EC2インスタンスには、パッチを適用するためにインターネットへの接続が必要ですが、パブリックにアクセスすることはできません。
これらの要件を満たすステップはどれですか？
A. インターフェイスエンドポイントを追加し、ルートテーブルを更新します。
B. インターネットゲートウェイを追加し、ルートテーブルを更新します。
C. 仮想ゲートウェイをVPCに追加し、ルートテーブルを更新します。
D. NATゲートウェイをVPCに追加し、ルートテーブルを更新します。
Answer: D
Explanation:
http://jayendrapatil.com/aws-vpc-nat/

NEW QUESTION: 4
バイナリ形式で示されている次のIPv4アドレスをドット付き10進数形式に変換します
10101100.01111011.00001101.10011101
A. 172.122.13.15
B. 172.124.13.57
C. 173.13.13.157
D. 172.123.13.157
Answer: D
Explanation:
An IPv4 address in dotted decimal format is constructed using binary arithmetic. In binary arithmetic, each bit within a group represents a power of two. Specifically, the first bit in a group represents 2 to the power of 0, the second bit represents 2 to the power of 1, the third bit represents 2 to the power of 2, and so on. Binary format is simple because each successive bit in a group is exactly twice the value of the previous bit.
The first octet is 128+32+8+4=172
The second octet 64+32+16+8+2+1=123
The third octet 8+4+1= 13
The fourth octet is 128+16+8+4+1= 157
Reference: https://en.wikipedia.org/wiki/IPv4