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NEW QUESTION: 1
A user has set the IAM policy where it denies all requests if a request is not from IP 10.10.10.1/32. The
other policy says allow all requests between 5 PM to 7 PM. What will happen when a user is requesting
access from IP 55.109.10.12/32 at 6 PM?
A. It is not possible to set a policy based on the time or IP
B. IAM will throw an error for policy conflict
C. It will allow access
D. It will deny access
Answer: D
Explanation:
When a request is made, the AWS IAM policy decides whether a given request should be allowed or
denied. The evaluation logic follows these rules:
By default, all requests are denied. (In general, requests made using the account credentials for
resources in the account are always allowed.)
An explicit allow policy overrides this default.
An explicit deny policy overrides any allows.
In this case since there are explicit deny and explicit allow statements. Thus, the request will be denied
since deny overrides allow.
Reference:
http://docs.aws.amazon.com/IAM/latest/UserGuide/AccessPolicyLanguage_EvaluationLogic.html

NEW QUESTION: 2
260.In WLAN wireless city scene, make a throughput test for the wireless terminal, under the same conditions which of the following description is correct?
A. TCP flow is greater than UDP flow
B. TCP flow is less than UDP flow
C. TCP flow is equal to UDP flow
D. none of the above is correct
Answer: B

NEW QUESTION: 3
Which two statements about I1Pv6 RA guard are true? (Choose two)
A. It provides security for tunneled IPv6 traffic
B. It blocks unauthorized ICMPv6 Type 134 packets
C. It supports host mode and router mode
D. It is supported in the ingress and egress directions
E. It blocks unauthorized ICMPv6 Type 133 packets
Answer: B,C

NEW QUESTION: 4

Refer to the exhibit. Which address and mask combination represents a summary of the routes learned by EIGRP?
A. 192.168.25.0 255.255.255.252
B. 192.168.25.28 255.255.255.240
C. 192.168.25.0 255.255.255.240
D. 192.168.25.28 255.255.255.240
E. 192.168.25.16 255.255.255.240
F. 192.168.25.16 255.255.255.252
Answer: E
Explanation:
The binary version of 20 is 10100.
The binary version of 16 is 10000.
The binary version of 24 is 11000.
The binary version of 28 is 11100.
The subnet mask is /28. The mask is 255.255.255.240.
Note:
From the output above, EIGRP learned 4 routes and we need to find out the summary of them: +
192.168.25.16+ 192.168.25.20+ 192.168.25.24+ 192.168.25.28
-> The increment should bE. 28 - 16 = 12 but 12 is not an exponentiation of 2 so we must choose
16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) =
255.255.255.240 So the best answer should be 192.168.25.16 255.255.255.240