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NEW QUESTION: 1

A. Option C
B. Option D
C. Option A
D. Option B
Answer: C

NEW QUESTION: 2
展示を参照してください。 EIGRPによって学習されたルートの要約を表すのは、どのアドレスとマスクの組み合わせですか。

A. 192.168.25.16 255.255.255.240
B. 192.168.25.0 255.255.255.240
C. 192.168.25.16 255.255.255.252
D. 192.168.25.28 255.255.255.252
E. 192.168.25.28 255.255.255.240
F. 192.168.25.0 255.255.255.252
Answer: A
Explanation:
The binary version of 20 is 10100.
The binary version of 16 is 10000.
The binary version of 24 is 11000.
The binary version of 28 is 11100.
The subnet mask is /28. The mask is 255.255.255.240.
Note:
From the output above, EIGRP learned 4 routes and we need to find out the summary of them:
+ 192.168.25.16
+ 192.168.25.20
+ 192.168.25.24
+ 192.168.25.28
-> The increment should bE. 28 ?16 = 12 but 12 is not an exponentiation of 2 so we must choose
16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) =
255.255.255.240
So the best answer should be 192.168.25.16 255.255.255.240

NEW QUESTION: 3
Refer to the exhibit.

Which three statements about this configuration are true? (Choose three.)
A. The static route is added to the global routing table and leaked from the VRF red.
B. The subnet 192.168.1.0 is unique to the VRF red routing table.
C. The static route appears in the VRF red routing table.
D. The default route appears in the global routing table.
E. The subnet 192.168.1.0 is unique to the global routing table.
F. 192.168.1.1 is reachable using any of the addresses on the router where the static route is configured.
Answer: C,D,E
Explanation:
This is an example of the route leaking feature. Here, this static route is created for the red VRF so it will be installed into the red VRF routing table, but the use of the global keyword will cause this default route to appear in the global routing table.