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NEW QUESTION: 1
次の表に示すリソースを含むAzureサブスクリプションがあります。

Certificateという名前の証明書！ Vaultに保存されます！
同じセキュリティプリンシパルを使用して、VM1とVM2にCertificate1へのアクセスを許可する必要があります。
あなたは何をするべきか？
A. Azure Active Directory（Azure AD）ユーザーを作成します。 Vaultlのアクセスポリシーを作成します。アクセスポリシーをユーザーに割り当てます。 VM1およびVM2にユーザーが割り当てたマネージIDを構成します。
B. マネージIDを作成します。 Vault1のKeyVault Readerの役割ベースのアクセス制御（RBAC）の役割を管理対象IDに割り当てます。 VM1およびVM2にシステムによって割り当てられた管理対象IDを構成します。
C. Azure Active Directory（Azure AD）ユーザーを作成します。 VaultlのKeyVault Readerロールベースアクセス制御（RBAC）ロールをユーザーに割り当てます。 VM1およびVM2にユーザーが割り当てた管理IDを構成します。
D. マネージIDを作成します。 Vaultlアクセスポリシーを管理対象IDに追加します。 VM1およびVM2にユーザーが割り当てた管理IDを構成します。
Answer: C

NEW QUESTION: 2
トポロジダイアグラムに示されているように、部分的な設定があり、RouterCに接続されている、多層SwitchCを設定することが任されています。
ホストH1とH2がサーバーS1に正常にpingできるように、SwitchCを構成する必要があります。 また、SwitchCはサーバーS1にpingを実行できる必要があります。
管理上の制約と要件のために、vlansを追加/削除したり、トランクリンクを作成したりしないでください。
会社のポリシーは、静的またはデフォルトのルーティングの使用を禁じています。 すべてのルートは、EIGRP 65010ルーティングプロトコルを介して学習する必要があります。
あなたはRouteCにアクセスすることはできません。 RouterCが正しく設定されています。 RouterCにはトランキングが設定されていません。
ルーティングされたインターフェイスは、可能であれば、サブネット上で最も低いホストを使用する必要があります。 このソリューションを実装するには、次のサブネットが利用できます。
- 10.10.10.0/24
- 190.200.250.32/27
- 190.200.250.64/27
ホストH1とH2は、正しいIPアドレスとデフォルトゲートウェイで構成されています。
SwitchCは、イネーブルパスワードとしてCiscoを使用します。
ルーティングは、図に示す特定のサブネットに対してのみ有効にする必要があります。
注：管理上の制限および要件のために、VLANを追加または削除したり、VLANポートの割り当てを変更したり、トランクを作成したりしないでください。 会社のポリシーは、静的またはデフォルトのルーティングの使用を禁じています。 すべてのルートは、EIGRPルーティングプロトコルを介して学習する必要があります。




A. \>ipconfig
We will get the default gateways as follows:
Host1:
+ Default gateway: 190.200.250.33
Host2:
+ Default gateway: 190.200.250.65
Now we have enough information to configure SwitchC (notice the EIGRP AS in this case is 650) Note: VLAN2 and VLAN3 were created and gi0/10, gi0/11 interfaces were configured as access ports so we don't need to configure them in this sim.
SwitchC# configure terminal
SwitchC(config)# int gi0/1
SwitchC(config-if)#no switchport -> without using this command, the simulator does not let you assign IP address on Gi0/1 interface.
SwitchC(config-if)# ip address 10.10.10.2 255.255.255.0 ->RouterC has used IP 10.10.10.1 so this is the lowest usable IP address.
SwitchC(config-if)# no shutdown
SwitchC(config-if)# exit
SwitchC(config)# int vlan 2
SwitchC(config-if)# ip address 190.200.250.33 255.255.255.224
SwitchC(config-if)# no shutdown
SwitchC(config-if)# int vlan 3
SwitchC(config-if)# ip address 190.200.250.65 255.255.255.224
SwitchC(config-if)# no shutdown
SwitchC(config-if)#exit
SwitchC(config)# ip routing (Notice: MLS will not work without this command) SwitchC(config)# router eigrp 65010 SwitchC(config-router)# network 10.10.10.0 0.0.0.255 SwitchC(config-router)# network 190.200.250.32 0.0.0.31 SwitchC(config-router)# network 190.200.250.64 0.0.0.31 NOTE: THE ROUTER IS CORRECTLY CONFIGURED, so you will not miss within it in the exam, also don't modify/delete any port just do the above configuration. Also some reports said the "no auto-summary" command can't be used in the simulator, in fact it is not necessary because the network
190.200.0.0/16 is not used anywhere else in this topology.
In order to complete the lab, you should expect the ping to SERVER to succeed from the MLS, and from the PCs as well.
Also make sure you use the correct EIGRP AS number (in the configuration above it is 650 but it will change when you take the exam) but we are not allowed to access RouterC so the only way to find out the EIGRP AS is to look at the exhibit above. If you use wrong AS number, no neighbor relationship is formed between RouterC and SwitchC.
In fact, we are pretty sure instead of using two commands "network 190.200.250.32 0.0.0.31 and
"network 190.200.250.64 0.0.0.31 we can use one simple command "network 190.200.0.0 because it is the nature of distance vector routing protocol like EIGRP: only major networks need to be advertised; even without "no auto-summary" command the network still works correctly. But in the exam the sim is just a flash based simulator so we should use two above commands, just for sure. But after finishing the configuration, we can use "show run" command to verify, only the summarized network 190.200.0.0 is shown.
B. この場合、インターVLANルーティングを設定する方法は2つあります。
+ Use RouterC as a "router on a stick" and SwitchC as a pure Layer2 switch. Trunking must be established between RouterC and SwitchC.
+ Only use SwitchC for interVLAN routing without using RouterC, SwitchC should be configured as a Layer 3 switch (which supports ip routing function as a router). No trunking requires.
The question clearly states "No trunking has been configured on RouterC" so RouterC does not contribute to interVLAN routing of hosts H1 & H2 -> SwitchC must be configured as a Layer 3 switch with SVIs for interVLAN routing.
We should check the default gateways on H1 & H2. Click on H1 and H2 and type the "ipconfig" command to get their default gateways.
Answer: B

NEW QUESTION: 3
Your Oracle database is deployed on-premises and has produced 100 TB database backup locally. You have a disaster recovery plan that requires you to create redundant database backups in Oracle Cloud Infrastructure (OCI). Once the initial backup is completed, the backup must be available for retrieval in less than 30 minutes to support the Recovery Time Objective (RTO) of your solution.
Which is the most cost effective option to meet these requirements?
A. Setup a FastConnect connection between on-premises data center and OCI. Then to use OCI CLI command to upload database backups to OCI Object Storage Standard tier as the final destination.
B. Use OCI Storage Gateway to transfer the backup files to OCI Object Storage Archive tier as the final destination.
C. Setup an IPsec VPNConnect between on-premises data center and OCI. Then to use OCI CLI command to upload database backups to OCI Object Storage Archive tier as the final destination.
D. Use OCI Storage Gateway to transfer the backup files to OCI Object Storage Standard tier as the final destination.
Answer: D

NEW QUESTION: 4
You are developing an application that includes methods named ConvertAmountand TransferFunds.
You need to ensure that the precision and range of the value in the amount variable is not lost when the TransferFunds()method is called.
Which code segment should you use?

A. Option B
B. Option A
C. Option D
D. Option C
Answer: B
Explanation:
Explanation/Reference:
Explanation:
The double keyword signifies a simple type that stores 64-bit floating-point values.
The float keyword signifies a simple type that stores 32-bit floating-point values.
References:
https://docs.microsoft.com/en-us/dotnet/csharp/language-reference/keywords/double