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250-600 Exam Simulator
  • Exam Code: 250-600
  • Exam Name: Carbon Black Application Control Technical Specialist
  • Version: V12.35
  • Q & A: 40 Questions and Answers
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NEW QUESTION: 1
この構成を調べます。
* CDB1は、プラガブルデータベースPDB $ SEED、PDB1、およびPDB2を含むOracle Database 12cリリース2データベースです。
* PDB$SEEDis openREAD ONLY
* PDB1is openREAD WRITE
* PDB2isMOUNTED.
* ORACLE_HOMEis/u01/app/oracle/product/18.1.0/dbhome_1.
データベースを現在のリリースにアップグレードする前に、次のコマンドを実行します。

どのデータベースに対してフィックスアップスクリプトが作成されますか?
A. CDB1、PDB $ SEED、およびPDB1のみ
B. CDB1およびPDB $ SEEDのみ
C. PDB $ SEED、PDB1、およびPDB2のみ
D. CDB1、PDB1、およびPDB2のみ
E. CDB1、PDB $ SEED、PDB1、およびPDB2
Answer: A

NEW QUESTION: 2
When residual risk is minimized:
A. control risk is reduced.
B. risk is transferable.
C. acceptable risk is probable.
D. transferred risk is acceptable.
Answer: C
Explanation:
Explanation
Since residual risk is the risk that remains after putting into place an effective risk management program, it is probable that the organization will decide that it is an acceptable risk if sufficiently minimized. Transferred risk is risk that has been assumed by a third party, therefore its magnitude is not relevant. Accordingly, choices B and D are incorrect since transferred risk does not necessarily indicate whether risk is at an acceptable level.
Minimizing residual risk will not reduce control risk.

NEW QUESTION: 3
You are a licensing specialist. Your customer is a company that has a Select License agreement.
Two years ago the company purchased 400 portable computers with Microsoft Windows
2000 Professional and Microsoft Office XP Professional preinstalled. Forty-five days ago the company purchased 100 desktops with Windows XP Professional and Office 2003
Professional OEM licenses.
Which of the companys current licenses are eligible to be enrolled in Software Assurance?
A. only the licenses for the portable computers
B. only the Windows XP Professional OEM licenses purchased with the new desktops
C. the Windows XP Professional and Office 2003 Professional OEM licenses purchased with the new desktops
D. all licenses for the desktops and the portable computers, when a new Select License agreement is signed
Answer: C

NEW QUESTION: 4
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to determine the total number of customers who have only loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
B. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
C. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct L WHERE D.CustNo = L.CustNo
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcct EXCEPT SELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
Answer: C
Explanation:
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp

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