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NEW QUESTION: 1
Which standard mechanism is used to secure the API Gateway in the IBM Reference implementation of a Cloud native Omnichannel application?
A. OpenID
B. WebSEAL
C. OAuth
D. SAML
Answer: A
Explanation:
Explanation
Explanation
Example: API Connect provides an OAuth Provider as well, allowing you to implement API Security.
References: https://github.com/ibm-cloud-architecture/refarch-cloudnative

NEW QUESTION: 2
There are three servers in the pool: 172.16.20.1, 172.16.20.2, and 172.16.20.3, with the virtual IP address
10.0.20.88.
A user CANNOT connect to an HTTP application. To understand the problem and find a solution, the LTM Specialist runs two concurrent traces on the LTM device, with the following results:
Trace on client side:
tcpdump: verbose output suppressed, use -v or -vv for full protocol decode listening on 0.0, link-type EN10MB (Ethernet), capture size 96 bytes
22:22:07.423759 IP 172.16.20.100.53875 > 10.0.20.88.80: S 998346084:998346084(0) win 5840 <mss
1460,sackOK,timestamp 67942058 0,nop,wscale 4>
22:22:07.424056 IP 10.0.20.88.80 > 172.16.20.100.53875: S 4671780:4671780(0) ack 998346085 win
4380 <mss 1460,nop,wscale 0,nop,nop,timestamp 2392362490 67942058,sackOK,eol>
22:22:07.424776 IP 172.16.20.100.53875 > 10.0.20.88.80: . ack 1 win 365 <nop,nop,timestamp 67942058
2392362490>
22:22:07.424790 IP 172.16.20.100.53875 > 10.0.20.88.80: P 1:149(148) ack 1 win 365
<nop,nop,timestamp 67942058 2392362490>
22:22:07.424891 IP 10.0.20.88.80 > 172.16.20.100.53875: . ack 149 win 4528 <nop,nop,timestamp
2392362491 67942058>
22:22:12.024850 IP 10.0.20.88.80 > 172.16.20.100.53875: R 1:1(0) ack 149 win 4528
6 packets captured
6 packets received by filter
0 packets dropped by kernel
Trace on server side:
tcpdump: verbose output suppressed, use -v or -vv for full protocol decode listening on internal, link-type EN10MB (Ethernet), capture size 96 bytes
22:22:07.424881 IP 172.16.20.100.53875 > 172.16.20.2.80: S 51116678:51116678(0) win 4380 <mss
1460,nop,wscale 0,nop,nop,timestamp 2392362491 0,sackOK,eol>
22:22:08.424893 IP 172.16.20.100.53875 > 172.16.20.2.80: S 51116678:51116678(0) win 4380 <mss
1460,nop,wscale 0,nop,nop,timestamp 2392363491 0,sackOK,eol>
22:22:09.625082 IP 172.16.20.100.53875 > 172.16.20.2.80: S 51116678:51116678(0) win 4380 <mss
1460,nop,wscale 0,nop,nop,timestamp 2392364691 0,sackOK,eol>
22:22:10.825194 IP 172.16.20.100.53875 > 172.16.20.2.80: S 51116678:51116678(0) win 4380 <mss
1460,sackOK,eol>
4 packets captured
4 packets received by filter
0 packets dropped by kernel
What should the LTM Specialist do to solve the problem?
A. Configure the virtual server to use SNAT.
B. Modify the monitor of the pool.
C. Enable the virtual server.
D. Edit the packet filter rules.
Answer: A

NEW QUESTION: 3
An attacker discovers a new vulnerability in an enterprise application. The attacker takes advantage of the
vulnerability by developing new malware. After installing the malware, the attacker is provided with access
to the infected machine.
Which of the following is being described?
A. Command injection
B. Zero-day exploit
C. Remote code execution
D. Session hijacking
Answer: B