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NEW QUESTION: 1
What is the number of production runs per year of computer chairs that would minimize the sum of carrying and setup costs for the coming year?
A. 0
B. 1
C. 2
D. 3
Answer: A
Explanation:
The EOQ minimizes the sum of carrying and setup costs. The EOQ is the amount at which carrying costs are equal to setup casts. Thus, plugging the data into the EOQ formula results in the following: C:\Documents and Settings\usernwz1\Desktop\1.PNG

Thus, if each lot consists of 1,000 units, five production runs per year are needed to meet the 5,000-unit demand. At this level, setup costs will total US $5,000 5 x $1,000). Carrying costs will also equal US $5,000 10 per unit carrying cost average inventory of 500 units).
Accordingly, total costs are minimized at US $10,000. Jed Ryerson Computer Furniture, Inc. RCF) manufactures a line of office computer chairs. The annual demand for the chairs is estimated to be 5,000 units. The annual cost tic. hold one unit in inventory is US $10 per year, and the cost to initiate a production run is US $1,000. There are no computer chairs on hand, and RCF has scheduled four equal production runs of computer chairs for the coming year, the first of which is to be run immediately. RCF has 250 business days per year, sales occur uniformly throughout the year, and production start-up is within one day. RCF is considering using the following formula for determining the economic order quantity EOQ):

If: A = cast to initiate a production run per purchase order D = annual unit demand K = cost of carrying one unit per year

NEW QUESTION: 2
An IBM Tivoli Storage Manager (TSM) database has grown to over 1 TB and taking 7 hours to back up. Which action could help reduce the amount of time to back up the TSM database?
A. increase the number of streams used by the database backup
B. turn compression on at the Tape drive
C. enable TSM Database space reclamation via the DSMSERV.opt
D. increase Server Recourceutilization to 10
Answer: A

NEW QUESTION: 3

A. CCTV
B. Mantrap
C. Guards
D. Biometrics
Answer: A

NEW QUESTION: 4
Sie haben eine Datenbank mit dem Namen SALES, in der die Verkaufsdaten und die Vertriebsmitarbeiter Ihres Unternehmens gespeichert sind.
Sie müssen eine Funktion erstellen, der eine ProductID übergeben wird und die dann eine Liste der SalesOrderID-Werte für Aufträge zurückgibt, die in Zukunft einem Verkäufer zugeordnet werden müssen. Die Funktion muss in der Lage sein, mehrere SalesOrderID-Werte zurückzugeben.
Ein Teil des richtigen Transact-SQL wurde im Antwortbereich unten bereitgestellt. Geben Sie den Code in den Antwortbereich ein, der das Problem löst und die angegebenen Ziele oder Anforderungen erfüllt. Sie können Code sowohl innerhalb als auch unterhalb des bereitgestellten Codes hinzufügen.


Verwenden Sie die Schaltfläche Syntax überprüfen, um Ihre Arbeit zu überprüfen. Alle Syntax- oder Rechtschreibfehler werden nach Zeilen- und Zeichenposition gemeldet.
Answer:
Explanation:
WHERE header.SalesPersonID IST NULL
Erläuterung
In Zeile 8 fügen Sie hinzu: IS NULL, um Folgendes zu erhalten:
CREATE FUNCTION dbo.OrdersWithNoSalesPerson (@ProductID INT)
KEHRT ZURÜCK
WIE
header.SalesOrderID
FROM Sales.SalesOrderDetail-Detail
INNER JOIN Sales.SalesOrderHeader-Header
on header.SalesOrderID = detail.SalesOrderID
WHERE header.SalesPersonID IST NULL
AND detail.ProductID = @ProductID;
GEHEN
Hinweis: IS NULL bestimmt, ob ein angegebener Ausdruck NULL ist. Wenn der Wert von expression NULL ist, gibt IS NULL TRUE zurück. Andernfalls wird FALSE zurückgegeben.
Verwenden Sie IS NULL oder IS NOT NULL anstelle von Vergleichsoperatoren (z. B. = oder! =), Um festzustellen, ob ein Ausdruck NULL ist. Vergleichsoperatoren geben UNKNOWN zurück, wenn eines oder beide Argumente NULL sind.
Verweise: https://msdn.microsoft.com/en-us/library/ms188795.aspx