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NEW QUESTION: 1
A DevOps Engineer is asked to implement a strategy for deploying updates to a web application with zero downtime. The application infrastructure is defined in AWS CloudFormation and is made up of an Amazon Route 53 record, an Application Load Balancer, Amazon EC2 instances in an EC2 Auto Scaling group, and Amazon DynamoDB tables. To avoid downtime, there must be an active instance serving the application at all times.
Which strategies will ensure the deployment happens with zero downtime? (Select TWO.)
A. In the CloudFormation template, modify the UpgradePolicy attribute for the CloudFormation stack and specify the Auto Scaling group that will be updated Configure MinSuccessfulInstancesPercent and PauseTime to ensure the deployment happens with zero downtime.
B. Add a new Application Load Balancer and Auto Scaling group to the CloudFormation template. Modify the AWS::AutoScaling::AutoScalingGroup resource and add an UpdatePolicy attribute to perform rolling updates.
C. Add a new Application Load Balancer and Auto Scaling group to the CloudFormation template. Deploy new changes to the inactive Auto Scaling group. Use Route 53 to change the active Application Load Balancer.
D. In the CloudFormation template, modify the AWS::AutoScaling::AutoscalingGroup resource and add an UpdatePolicy attribute to define the required elements for a deployment with zero downtime.
E. In the CloudFormation template, modify the AWS:: AutoScaling::DeploymentUpdates resource and add an UpdatePolicy attribute to define the required elements for a deployment with zero downtime.
Answer: C,D

NEW QUESTION: 2
You have a Windows Server 2016 Hyper-V failover cluster that contains two nodes named Node1 and Node2.
On Node1, you create a virtual machine named VM01 by using Hyper-V Manager.
You need to configure VM01 to move to Node2 automatically if Node1 becomes unavailable.
What should you do?
A. From Windows PowerShell, run the Enable-VMReplication cmdlet.
B. From Hyper-V Manager, click VM01, and click Enable Replication.
C. Form Failover Cluster Manager, run the Configure Role actions.
D. From Hyper-V Manager, click Node1, and then modify the Hyper-V settings.
Answer: C
Explanation:
References:
http://windowsitpro.com/hyper-v/make-vm-highly-available-windows-server-2012

NEW QUESTION: 3
Which is evidenced by the Business Case?
A. Information about what will be subject to review
B. Continuing affordability of the programme
C. Responsibility for managing the Business Change Team
D. Risk responses for the initial programme risks
Answer: B

NEW QUESTION: 4
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following columns:

You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
C. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
F. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
G. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
H. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
Answer: G
Explanation:
Explanation
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php