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H28-153_V1.0 Exam Simulator
  • Exam Code: H28-153_V1.0
  • Exam Name: HCSA-Development-AICC V1.0
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NEW QUESTION: 1
The locations of the vehicles of your company are available as coordinates. You need to display only the current location of a vehicle on a Virtual Earth 6.0 base map layer. What are two possible code segments you can use to achieve this goal? (Each correct answer presents a complete solution. Choose two.)
A. map = new VEMap('myMap'); map.LoadMap(); layer = new VEShapeLayer(); map.AddShapeLayer(layer); shape = new VEShape(VEShapeType.Pushpin, new VELatLong(longitude, latitude)); layer.AddShape(shape);
B. map = new VEMap('myMap'); map.LoadMap(); shape = new VEShape(VEShapeType.Pushpin, new VELatLong(latitude, longitude)); map.AddShape(shape);
C. map = new VEMap('myMap'); map.LoadMap(); map.AddPushpin(new VELatLong(longitude, latitude));
D. map = new VEMap('myMap'); map.LoadMap(); map.AddPushpin(new VELatLong(latitude, longitude));
E. map = new VEMap('myMap'); map.LoadMap(); layer = new VEShapeLayer(); map.AddShapeLayer(layer); shape = new VEShape(VEShapeType.Pushpin, new VELatLong(latitude, longitude)); layer.AddShape(shape);
Answer: B,D

NEW QUESTION: 2
Refer to the exhibit.

Users report that IP addresses cannot be acquired from the DHCP server. The DHCP server is configured as shown. About 300 total nonconcurrent users are using this DHCP server, but none of them are active for more than two hours per day. Which action fixes the issue within the current resources?
A. Modify the subnet mask to the network 192.168.1.0 255.255.254.0 command in the DHCP pool
B. Configure the DHCP lease time to a bigger value
C. Add the network 192.168.2.0 255.255.255.0 command to the DHCP pool
D. Configure the DHCP lease time to a smaller value
Answer: D

NEW QUESTION: 3
The CUSTOMERS table has these columns:
The CUSTOMER_ID column is the primary key for the table.
You need to determine how dispersed your customer base is.
Which expression finds the number of different countries represented in the CUSTOMERS table?
A. COUNT DISTINCT UPPER(country_address)
B. COUNT(UNIQUE(UPPER(country_address)))
C. COUNT(DISTINCT (UPPER(country_address)))
D. COUNT(UPPER(country_address))
E. COUNT(DIFF(UPPER(country_address)))
Answer: C

NEW QUESTION: 4

A. Option B
B. Option A
C. Option C
D. Option D
Answer: B

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