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NEW QUESTION: 1
Windows Server 2016を実行するServer1という名前のオンプレミスファイルサーバーがあります。
Azureファイル共有を含むAzureサブスクリプションがあります。
Azure File Sync Storage Sync Serviceをデプロイし、同期グループを作成します。
Server1からAzureにファイルを同期する必要があります。
順番に実行する必要がある3つのアクションはどれですか？回答するには、適切なアクションをアクションのリストから回答エリアに移動し、正しい順序に並べます。

Answer:
Explanation:

Explanation

Step 1: Install the Azure File Sync agent on Server1
The Azure File Sync agent is a downloadable package that enables Windows Server to be synced with an Azure file share Step 2: Register Server1.
Register Windows Server with Storage Sync Service
Registering your Windows Server with a Storage Sync Service establishes a trust relationship between your server (or cluster) and the Storage Sync Service.
Step 3: Add a server endpoint
Create a sync group and a cloud endpoint.
A sync group defines the sync topology for a set of files. Endpoints within a sync group are kept in sync with each other. A sync group must contain one cloud endpoint, which represents an Azure file share and one or more server endpoints. A server endpoint represents a path on registered server.
References: https://docs.microsoft.com/en-us/azure/storage/files/storage-sync-files-deployment-guide

NEW QUESTION: 2


Answer:
Explanation:

Explanation

NEW QUESTION: 3
A database view is the results of which of the following operations?
A. Join, Project, and Create.
B. Join, Project, and Select.
C. Join and Select.
D. Join, Insert, and Project.
Answer: B
Explanation:
What is Relational Algebra:
1.The formal description of how a relational database operates.
2.The mathematics which underpin SQL operations.
A number of operations can be performed in relational algebra to build relations and operate on
the data.
Five operations are primitives (Select, Project, Union, Difference and Product) and the other
operations can be defined in terms of those five. A View is defined from the operations of Join,
Project, and Select.
For the purpose of the exam you must remember the following terms from relational algebra and
their SQL equivalent:
Tuple = Row, Entry
Attribute = Column
Relation or Based relation = Table
See the extract below from the ISC2 book:
Each table, or relation, in the relational model consists of a set of attributes and a set of tuples
(rows) or entries in the table. Attributes correspond to a column in a table. Attributes are unordered
left to right, and thus are referenced by name and not by position. All data values in the relational
model are atomic. Atomic values mean that at every row/column position in every table there is
always exactly one data value and never a set of values. There are no links or pointers connecting
tables; thus, the representation of relationships is contained as data in another table.
A tuple of a table corresponds to a row in the table. Tuples are unordered top to bottom because a
relation is a mathematical set and not a list. Also, because tuples are based on tables that are
mathematical sets, there are no duplicate tuples in a table (sets in mathematics by definition do
not include duplicate elements).
The primary key is an attribute or set of attributes that uniquely identifies a specific instance of an
entity. Each table in a database must have a primary key that is unique to that table. It is a subset
of the candidate key.
Reference used for this question:
Hernandez CISSP, Steven (2012-12-21). Official (ISC)2 Guide to the CISSP CBK, Third Edition
((ISC)2 Press) (Kindle Locations 12262-12269). Auerbach Publications. Kindle Edition.
and
KRUTZ, Ronald L. & VINES, Russel D., The CISSP Prep Guide: Mastering the Ten Domains of
Computer Security, 2001, John Wiley & Sons, Page 46.
and
http://db.grussell.org/slides/rel%20algebra%201.ppt
NOTE:
SQL offers three classes of operators: select, project, and join.
The select operator serves to shrink the table vertically by eliminating unwanted rows (tuples).
The project operator serves to shrink the table horizontally by removing unwanted columns
(attributes).
And the join operator allows the dynamic linking of two tables that share a common column value.
The join operation is achieved by stating the selection criteria for two tables and equating them
with their common columns.
Most commercial implementations of SQL do not support a project operation, instead projections
are achieved by specifying the columns desired in the output. This is why the Project operator is
not well known as it is fading away from most databases.