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DY0-001 Exam Simulator
  • Exam Code: DY0-001
  • Exam Name: CompTIA DataX Certification Exam
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NEW QUESTION: 1
A 2-day-old infant boy has been diagnosed with an atrial septal defect due to a persistent patent foramen ovale.
When explaining the diagnosis to the mother, the nurse includes in the discussion the function of the foramen ovale. In fetal circulation, the foramen ovale allows a portion of the blood to bypass the:
A. Liver
B. Pulmonary system
C. Superior vena cava
D. Left ventricle
Answer: B
Explanation:
(A)
The foramen ovale permits a percentage of the blood to shunt from the right atrium to the left atrium. The blood then goes to the left ventricle, permitting systemic fetal circulation with blood containing a higher O2 saturation. (B) As the blood shunts from the right atrium to the left atrium, the pulmonary system is bypassed. The fetus receives O2 from the maternal circulation, thereby permitting the partial bypass of the pulmonary system. (C) The foramen ovale is locatedin the atrial septum of the heart and does not affect the liver.
(D)
The superior vena cava returns blood to the heart, bringing blood to the location of the foramen ovale.

NEW QUESTION: 2
Which two methods are used to obtain Avaya Aura Communication Manager (CM)software version information? (Choose two.)
A. In Avaya Aura System Manager (SMGR), navigate to Services > Inventory > Managed Elements.
B. In Linux, issue the software version show.command.
C. In Linux, issue the swversion. command.
D. In CM SMI, navigate to Administration > Server Maintenance > Server > Software Version.
E. In CM SAT, issue the display software version. command.
Answer: C,D

NEW QUESTION: 3

class Fibonacci extends RecursiveTask<Integer> {
final int n;
Fibonacci (int n) { this.n = n }
Integer compute () {
if (n <= 1)
return n;
Fibonacci f1 = new Fibonacci (n - 1);
f1.fork;
Fibonacci f2 = new Fibonacci (n - 2);
return f2.compute() + f1.join; // Line **
}
}
Assume that line ** is replaced with:
return f1.join() + f2.compute(); // Line **

A. Option F
B. Option D
C. Option B
D. Option A
E. Option E
F. Option C
Answer: C
Explanation:
Changing the code is not useful. In the original code (return f2.compute() + f1.join; )
f1 and f2 are run in parallel. The result is joined.
With the changed code (return f1.join() + f2.compute();) f1 is first executed and finished, then is f2
executed.
Note 1: The join method allows one thread to wait for the completion of another.
If t is a Thread object whose thread is currently executing,
t.join();
causes the current thread to pause execution until t's thread terminates.
Note 2: New in the Java SE 7 release, the fork/join framework is an implementation of the
ExecutorService interface that helps you take advantage of multiple processors. It is designed for
work that can be broken into smaller pieces recursively. The goal is to use all the available
processing power to enhance the performance of your application.
As with any ExecutorService, the fork/join framework distributes tasks to worker threads in a
thread pool. The fork/join framework is distinct because it uses a work-stealing algorithm. Worker
threads that run out of things to do can steal tasks from other threads that are still busy.
Reference: The Java Tutorials, Joins, Fork/Join

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