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NEW QUESTION: 1
What plug-in integrates with Lotus Notes and gives the user the ability to update their status within their inbox?
A. Notes Integrator plug-in
B. Social Media plug-in
C. Status Updates plug-in
D. Media-Share plug-in
Answer: C

NEW QUESTION: 2
Which question would you use to uncover a workplace productivity opportunity?
A. What challenges are you seeing in your virtualized environment?
B. How important is mobility to your business?
C. How are you handling demanding, data-intensive workloads and exponential data
growth?
D. How do you define good utilization?
Answer: B

NEW QUESTION: 3
Your network contains two subnets. The subnets are configured as shown in the following table.

You have a server named Server1 that runs Windows Server 2012 R2. Server1 is connected to LAN1.
You run the route print command as shown in the exhibit. (Click the Exhibit button.)

You need to ensure that Server1 can communicate with the client computers on LAN2.
What should you do?
A. Change the default gateway address.
B. Change the metric of the 10.10.1.0 route.
C. Set the state of the Microsoft ISATAP Adapter #2 interface to disable.
D. Set the state of the Teredo interface to disable.
Answer: A
Explanation:
Explanation/Reference:
Explanation:
The exhibit shows the default gateway address to be that of LAN1. This should be changed to the LAN2 gateway address to allow client computers access on LAN2.
In general, the first and last addresses in a subnet are used as the network identifier and broadcast address, respectively. All other addresses in the subnet can be assigned to hosts on that subnet. For example, IP addresses of networks with subnet masks of at least 24 bits ending in .0 or .255 can never be assigned to hosts. Such "last" addresses of a subnet are considered "broadcast" addresses and all hosts on the corresponding subnet will respond to it. Theoretically, there could be situations where you can assign an address ending in .0: for example, if you have a subnet like 192.168.0.0/255.255.0.0, you are allowed to assign a host the address 192.168.1.0. It could create confusion though, so it's not a very common practice.
Example10.6.43.0 with subnet 255.255.252.0 (22 bit subnet mask) means subnet ID 10.6.40.0, a host address range from 10.6.40.1 to 10.6.43.254 and a broadcast address10.6.43.255. So in theory, your example 10.6.43.0 would be allowed as a valid host address. The default gateway address should not end in .0 with the /24 address.
References:
Training Guide: Installing and Configuring Windows Server 2012 R2, Chapter 4: Deploying domain controllers, Lesson 4: Configuring IPv6/IPv4 Interoperability, p. 254-256