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NEW QUESTION: 1
ユーザーがデータベースのパフォーマンスの低下について不満を言っています。
ユーザーのセッションが特定のタイプのI / Oアクティビティを待機しているかどうかを確認したいとします。セッションで少なくとも1回待機したすべての待機を表示するビューはどれですか？
A. V $ SESSION_EVENT
B. V $ SESSION
C. V $ SESSTAT
D. V $ SESSION_WAIT_CLASS
E. V $ SESSION_WAIT
Answer: D

NEW QUESTION: 2
Refer to the exhibit.

The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and
208.149.23.96?
A. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0
2 08.149.23.96[110/3] via 190.173.23.10, 00:00:16, FastEthemet0/0
B. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0
208.149.23.96[110/13] via 190.173.23.10, 00:00:16, Serial1/0
208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
C. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0
2 08.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
D. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0
2 08.149.23.96[110/3] via 190.173.23.10, 00:00:16, Serial1/0
Answer: C
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 /
Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the cost is 12 (learned from Router_A) + 1 = 13 for both subnets ->
The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps =
64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link ->
Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0.
In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.

NEW QUESTION: 3
Which statement is true about NFS export in Cluster-Mode?
A. Export policies and rules are stored in the RDB.
B. Both A and B
C. Export policies are created and modified by editing /etc/exports.
D. Both B and C
E. Exports can be either persistent or temporary.
Answer: A

NEW QUESTION: 4
Which step sorts the observations of a permanent SAS data set by two variables and stores the sorted observations in a temporary SAS data set?
A. proc sort out=EMPLOYEES data=EMPSORT;
by Lname and Fname;
run;
B. proc sort data=SASUSER.EMPLOYEES out=SASUSER.EMPSORT;
by Lname and Fname;
run;
C. proc sort out=SASUSER.EMPLOYEES data=WORK.EMPSORT;
by Lname Fname;
run;
D. proc sort data=SASUSER.EMPLOYEES out=EMPSORT;
by Lname Fname;
run;
Answer: D