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NEW QUESTION: 1
View the Exhibit and examine the structure of ORDERS and CUSTOMERS tables.

There is only one customer with the CUST_LAST_NAME column having value Roberts. Which INSERT statement should be used to add a row into the ORDERS table for the customer whose CUST_LAST_NAME is Roberts and CREDIT_LIMIT is 600?
A. INSERT INTO orders
VALUES (1, '10-mar-2007', 'direct',
(SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND
credit_limit=600), 1000);
B. INSERT INTO orders (order_id, order_date, order_mode,
(SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND
credit_limit=600), order_total)
VALUES(1, '10-mar-2007', 'direct', &&customer_id, 1000);
C. INSERT INTO orders (order_id, order_date, order_mode,
(SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND
credit_limit=600), order_total)
VALUES(1, '10-mar-2007', 'direct', &customer_id, 1000);
D. INSERT INTO(SELECT o.order_id, o.order_date, o.order_mode, c.customer_id, o.order_total FROM orders o, customers c WHERE o.customer_id = c.customer_id AND c.cust_last_name='Roberts' ANDc.credit_limit=600 )
VALUES (1, '10-mar-2007', 'direct', (SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND
credit_limit=600), 1000);
Answer: A

NEW QUESTION: 2
Sie haben einen Server mit dem Namen Server1, auf dem Windows Server 2012 R2 ausgeführt wird.
Auf Server1 öffnen Sie die Computerverwaltung wie in der Ausstellung gezeigt. (Klicken Sie auf die Schaltfläche "Ausstellen".)

Sie müssen sicherstellen, dass Sie ein 3-TB-Volume auf Datenträger 1 erstellen können.
Was solltest du zuerst tun?
A. Erstellen Sie einen Speicherpool.
B. Konvertiert den Datenträger in einen GPT-Datenträger.
C. Erstellen Sie eine virtuelle Festplatte und schließen Sie sie an.
D. Konvertiert die Festplatte in eine dynamische Festplatte.
Answer: B

NEW QUESTION: 3
次のうち有効なホストIPv6アドレスはどれですか？ （該当するものをすべて選択してください）
A. 2001:bad:2345:a:b::cef/128
B. 2001:000a:lb2c::/64
C. 2001:aaaa: 1234:456c: 1/64
D. ff02:a:b:c::l/64
E. 2fff:f:f:f::f/64
F. ff02:33ab:l:32::2/128
Answer: A,C
Explanation:
Option B is valid, assuming theres a faulty colon : in the IPv6 Address, just before the last 1, that is: 2001:aaaa:1234:456c::1/64 Option F is valid, dispite its odd network mask (128 bits), sometimes used in tunnel links.
Incorrect answer:
Option A is invalid, since it is a Multicast address
Option C seems to be invalid because the 3rd group of characters includes an l (lb2c), but if it is a 1 instead of an l (faulty scan) and the required options are 3 instead of 2, then this address is still valid (2001:000a:1b2c::/64), because the 4th group of characters would be 0000 (remember that we can represent a continuous sequence of zeros by ::).
Option D is definitely invalid since it is a reserved address. As states the IANA online :document about the IPv6 Unicast Global Addresses, the range below is reserved, not allocated to any RIR (Regional Internet Registry):
2E00:0000::/7 IANA 1999-07-01 RESERVED
2FFF is a reserved address, because 2E00::/7 (with 7 bits of mask) means that 2FFF:: is included in this range (no matter the number of bits of the mask).