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AD0-E328 Exam Simulator
  • Exam Code: AD0-E328
  • Exam Name: Adobe Campaign Classic Architect
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  • Q & A: 40 Questions and Answers
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NEW QUESTION: 1
あなたの会社には、Microsoft Enterprise Agreementの一部であるいくつかのAzureサブスクリプションがありますか?
会社のコンプライアンスチームは、Ware Monitorを使用して自動アラートを作成します。
Enterprise契約に新しいサブスクリプションが追加されたときにアラートを自動的に適用するソリューションを推奨する必要があります。
推奨事項に何を含めるべきですか?
A. Azure Resource Manager templates
B. Azure log Analytics alerts
C. Azure Policy
D. Azure Automation runboote
E. Azure Monitor action groups
Answer: C

NEW QUESTION: 2
How to Remove the Bones from Poultry?
Many recipes for chicken, turkey, or duck require that the bones be removed from the bird, leaving the body as intact as possible so that it may be closed up, stuffed, and then cooked as a normal bird. De- boned poultry is particularly tender and is suitable for deep-frying as well as roasting. Many may find this requirement to be daunting, but it is, in fact, quite simple. Here, I present a very straightforward method for removing the bones from a whole bird.
These are the basic steps:
First, place the bird breast side down on a cutting board or other suitable surface. Using a sharp paring knife, make a cut down the full length of the back.
Next, begin to cut the meat away from the bones on one side, working from the front of the bird to the back. Stay as close to the bone as possible, and scrape the meat free. As you get to the thigh and wing, cut the tendons and separate them from the skeleton. Take the bone out of the thigh, but leave the ones that are inside the drumsticks and wings. Then, repeat this step on the other side of the bird.
Continue until you are able to remove the breastbone. You will have to work this free of the surrounding meat until you can extract it from the body cavity. Be careful not to cut the skin.
Flatten the bird as much as possible on the cutting surface, skin side down; then season with salt and pepper.
Finally, close the back of the bird by sewing it up with a large gauge needle and thick cotton kitchen thread.
Curved upholstery needles work well for this.
Now, you can stuff the bird and roast it just like a normal bird. When preparing the stuffing, keep in mind that there will be more room inside a de-boned bird than in one that has retained its skeleton, so more stuffing will be required. Alternatively, you can use this technique to prepare Turducken, where a de-boned chicken is placed within a duck, which is placed within a turkey. Turducken is a Thanksgiving specialty in many parts of the country.
Why is more stuffing required for a de-boned bird than for a normal bird?
A. The stuffing is packed more tightly
B. Larger birds are used for de-boning
C. The stuffing shrinks when you fry the bird
D. They are more loosely sewn than normal birds
E. The space once taken up by the bones must also be filled
Answer: E
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 3
Which three statements are true about Cryptographically Generated Addresses for IPv6? (Choose three.)
A. The minimum RSA key length is 512 bits.
B. They are derived by generating a random 128-bit IPv6 address based on the public key of the node.
C. They prevent spoofing and stealing of existing IPv6 addresses.
D. SHA or MD5 is used during their computation.
E. The SHA-1 hash function is used during their computation.
F. They are used for securing neighbor discovery using SeND.
Answer: C,E,F
Explanation:
A Cryptographically Generated Address (CGA) is an Internet Protocol Version 6 (IPv6) address that has a host identifier computed from a cryptographic hash function. This procedure is a method for binding a public signature key to an IPv6 address in the Secure Neighbor Discovery Protocol (SEND).A Cryptographically Generated Address is formed by replacing the least-significant 64 bits of the 128-bit IPv6 address with the cryptographic hash of the public key of the address owner. The messages are signed with the corresponding private key. Only if the source address and the public key are known can the verifier authenticate the message from that corresponding sender. This method requires no public key infrastructure. Valid CGAs may be generated by any sender, including a potential attacker, but they cannot use any existing CGAs.SHA-1 hash function is used to during computation:
1 procedure generateCGA(Sec, subnetPrefix, publicKey, extFields): 2 modifier := random(0x00000000000000000000000000000000, // 16 octets (128 bits) 3 0xffffffffffffffffffffffffffffffff) 4 5 label1: 6 concat := concatenate(modifier, 0x000000000000000000, // 9 zero octets 7 publicKey, extFields) 8 9 digest := SHA1(concat) 10 Hash2 := digest[0:14] // 14*8 = 112 leftmost bits 11 12 if Sec 0 and Hash2[0:2*Sec] 0: // 2*Sec*8 = 16*Sec leftmost bits 13 modifier := modifier + 1 14 goto label1 15 end if 16 17 collCount := 0x00 // 8-bit collision count

NEW QUESTION: 4
A developer has the controller class below.

Which code block will run successfully in an execute anonymous window?
A. myFooController m = new myFooController();System.assert(m.prop ==1);
B. myFooController m = new myFooController();System.assert(m.prop ==null);
C. myFooController m = new myFooController();System.assert(m.prop ==0);
D. myFooController m = new myFooController();System.assert(m.prop !=null);
Answer: B

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