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NEW QUESTION: 1
新しいセキュリティ管理者が初めて脆弱性スキャナを実行し、システムを停止させました。 次の種類のスキャンのどれが最も停止を引き起こした可能性がありますか？
A. 非侵入型の資格情報付きスキャン
B. 侵入型の資格情報付きスキャン
C. 侵入的で資格のないスキャン
D. 侵入型の非資格情報スキャン
Answer: D

NEW QUESTION: 2
Label Makerアプリケーションの新しいバージョンを展開する必要があります。
順番に実行する必要がある3つのアクションはどれですか？
回答するには、適切なアクションをアクションのリストから回答エリアに移動し、正しい順序に並べます。

Answer:
Explanation:

Explanation
Create an alias of the image with fully qualified path to the registry
Log in to the registry and push image
Restart the cluster.

NEW QUESTION: 3
Lab Simulation - CLI Configuration



Attention:
In practical examinations, please note the following, the actual information will prevail.
1. Name of the router is xxx
2. Enable. secret password is xxx
3. Password In access user EXEC mode using the console is xxx
4. The password to allow telnet access to the router is xxx
5. IP information
Answer:
Explanation:
Router>enable
Router#config terminal
Router(config)#hostname Gotha
2) Enable-secret password (cisco10):
Gotha(config)#enable secret mi222ke
3) Set the console password to G8tors1:
Gotha(config)#line console 0
Gotha(config-line)#password G8tors1
Gotha(config-line)#login
Gotha(config-line)#exit
4) Set the Telnet password to dun63lap:
Gotha(config)#line vty 0 4
Gotha(config-line)#password dun63lap
Gotha(config-line)#login
Gotha(config-line)#exit
5) Configure Ethernet interface (on the right) of router Gotha:
Ethernet network 209.165.201.0 /27 - Router has the fourth assignable host address in subnet.
Ethernet Interface on router R2 is Fast Ethernet 0/0 as per the exhibit First we need to identify the subnet mask Network: 209.165.201.0 /27 Subnet mask: /27: 27 bits = 8 + 8 + 8 + 3
=8(bits).8(bits).8(bits) .11100000 (3bits)
=255.255.255.11100000
=11100000 = 128+64+32+0+0+0+0+0
= 224
Subnet mask: 255.255.255.224
Different subnet networks and there valid first and last assignable host address range for above subnet mask are Subnet Networks :::::: Valid Host address range :::::: Broadcast address
209.165.201.0 :::::: 209.165.201.1 - 209.165.201.30 ::::: 209.165.201.31
209.165.201.32 :::::: 209.165.201.33 - 209.165.201.62 ::::: 209.165.201.63
209.165.201.64 :::::: 209.165.201.65 - 209.165.201.94 :::::: 209.165.201.95
209.165.201.96 :::::: 209.165.201.97 - 209.165.201.126 :::::: 209.165.201.127
209.165.201.128 :::::: 209.165.201.129 - 209.165.201.158 :::::: 209.165.201.159
209.165.201.160 :::::: 209.165.201.161 - 209.165.201.190 :::::: 209.165.201.191
209.165.201.192 :::::: 209.165.201.193 - 209.165.201.222 :::::: 209.165.201.223
209.165.201.224 :::::: 209.165.201.225 - 209.165.201.254 :::::: 209.165.201.255 Use above table information for network 209.165.201.0 /27 to identify First assignable host address: 209.165.201.1 Last assignable host address: 209.165.201.30 Fourth assignable host address: 209.165.201.4 Assign the fourth assignable host address to Fa0/0 interface of Gotha router:
Gotha(config)#interface Fa0/0
Gotha(config-if)#ip address 209.165.201.4 255.255.255.224
Gotha(config-if)#no shutdown
Gotha(config-if)#exit
6) Configure Serial interface (on the left) of router Gotha:
Serial Network is 192.0.2.176 /28 - Router has the last assignable host address in subnet.
Serial Interface on R2 is Serial 0/0/0 as per the exhibit
First we need to identify the subnet mask
Network: 192.0.2.176 /28
Subnet mask: /28: 28bits = 8bits+8bits+8bits+4bits
=8(bits).8(bits).8(bits) .11110000 (4bits)
=255.255.255.11100000
=11100000 = 128+64+32+16+0+0+0+0
= 240
Subnet mask: 255.255.255.240
Different subnet networks and there valid first and last assignable host address range for above subnet mask are Subnet Networks ::::: Valid Host address ::::::::::: Broadcast address
192.0.2.0 :::::: 192.0.2.1 - 192.0.2.14 ::::::: 192.0.2.15
192.0.2.16 ::::::: 192.0.2.17 - 192.0.2.30 ::::::: 192.0.2.31
192.0.2.32 :::::::: 192.0.2.33 - 192.0.2.46 :::::: 192.0.2.47
192.0.2.48 :::::: 192.0.2.49 - 192.0.2.62 ::::::: 192.0.2.64
192.0.2.64 ::::::: 192.0.2.65 - 192.0.2.78 ::::::: 192.0.2.79
192.0.2.80 :::::::: 192.0.2.81 - 192.0.2.94 :::::: 192.0.2.95
192.0.2.96 :::::: 192.0.2.97 - 192.0.2.110 ::::::: 192.0.2.111
192.0.2.112 ::::::: 192.0.2.113 - 192.0.2.126 ::::::: 192.0.2.127
192.0.2.128 :::::::: 192.0.2.129 - 192.0.2.142 :::::: 192.0.2.143
192.0.2.144 :::::: 192.0.2.145 - 192.0.2.158 ::::::: 192.0.2.159
192.0.2.160 ::::::: 192.0.2.161 - 192.0.2.174 ::::::: 192.0.2.175
192.0.2.176 :::::::: 192.0.2.177 - 192.0.2.190 :::::: 192.0.2.191
and so on ....
Use above table information for network 192.0.2.176 /28 to identify
First assignable host address: 192.0.2.177
Last assignable host address: 192.0.2.190
We need to configure Last assignable host address (192.0.2.190) on serial 0/0/0 using the subnet mask 255.255.255.240 Assign the last assignable host address to S0/0/0 interface of Gotha router:
Gotha(config)#interface S0/0/0 (or use interface S0/0 if not successful) Gotha(config-if)#ip address 192.0.2.190 255.255.255.240 Gotha(config-if)#no shutdown Gotha(config-if)#exit
7) Configure RIP v2 routing protocol:
Gotha(config)#router rip
Gotha(config-router)#version 2
Gotha(config-router)#network 209.165.201.0
Gotha(config-router)#network 192.0.2.176
Gotha(config-router)#end
Save the configuration:
Gotha#copy running-config startup-config
Finally, you should use the ping command to verify all are working properly!

NEW QUESTION: 4
Note: This question is part of a series of questions that present the same scenario. Each question in the series contains a unique solution that might meet the stated goals. Some question sets might have more than one correct solution, while others might not have a correct solution.
After you answer a question in this sections, you will NOT be able to return to it. As a result, these questions will not appear in the review screen.
You are working on an Azure Machine Learning experiment.
You have the dataset configured as shown in the following table.

You need to ensure that you can compare the performance of the models and add annotations to the results.
Solution: You consolidate the output of the Score Model modules by using the Add Rows module, and then use the Execute R Script module.
Does this meet the goal?
A. No
B. Yes
Answer: A
Explanation:
Explanation/Reference:
Explanation:
References:
https://msdn.microsoft.com/en-us/library/azure/dn905915.aspx