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NEW QUESTION: 1
Which of the following statements are true?
(i) Defects are likely to be found earlier in the development process by using reviews rather than static analysis.
(ii) Walkthroughs require code but static analysis does not require code.
(iii) Informal reviews can be performed on code and specifications.
(iv) Dynamic techniques are generally used before static techniques.
(v) Dynamic techniques can only be used after code is ready to be executed.
A. (i), (ii), (vi).
B. (i), (iv), (v).
C. (i), (iii), (v).
D. (ii), (iii), (v).
Answer: C
Explanation:
Explanation/Reference:
Explanation:
The other answers are incorrect because:
(ii) Walkthroughs do not require code and static analysis does require code.
(iv) Static techniques do not execute the code and therefore can be run before and after the code is ready for execution.

NEW QUESTION: 2
Refer to the exhibit.

You executed the show crypto ipsec sa command to troubleshoot an IPSec issue. What problem does the given output indicate?
A. ISAKMP was unable to find a matching SA.
B. IKEv2 failed to establish a phase 2 negotiation.
C. IKEv2 was used in aggressive mode.
D. The Crypto ACL is different on the peer device.
Answer: D

NEW QUESTION: 3
You administer a SQL Server 2012 server that contains a database named SalesDB. SalesDb contains a schema named Customers that has a table named Regions. A user named UserA is a member of a role named Sales.
UserA is granted the Select permission on the Regions table. The Sales role is granted the Select permission on the Customers schema.
You need to ensure that UserA is disallowed to select from any of the tables in the Customers schema.
Which Transact-SQL statement should you use?
A. DENY SELECT ON Object::Regions FROM UserA
B. DENY SELECT ON Schema::Customers FROM Sales
C. REVOKE SELECT ON Object::Regions FROM UserA
D. EXEC sp_addrolemember 'Sales', 'UserA'
E. EXEC spdroprolemember 'Sales', 'UserA'
F. REVOKE SELECT ON Schema::Customers FROM UserA
G. DENY SELECT ON Schema::Customers FROM UserA
H. REVOKE SELECT ON Schema::Customers FROM Sales
I. DENY SELECT ON Object::Regions FROM Sales
J. REVOKE SELECT ON Object::Regions FROM Sales
Answer: G
Explanation:
http://msdn.microsoft.com/en-us/library/ms188369.aspx http://msdn.microsoft.com/en-us/library/ms187750.aspx http://msdn.microsoft.com/en-us/library/ff848791.aspx

NEW QUESTION: 4
展示を参照してください。

Link1は銅線接続で、Link2はファイバー接続です。ファイバポートは、すべての転送のプライマリポートである必要があります。 SW2でのshow spanning-treeコマンドの出力は、ファイバーポートがスパニングツリーによってブロックされていることを示しています。エンジニアがSW2のGO / 1でspanning-tree port-priority 32コマンドを入力しましたが、ポートはブロックされたままです。問題を解決するには、Link2に接続されているポートでどのコマンドを入力する必要がありますか？
A. SW1にスパニングツリーポートプライオリティ224を入力します。
B. SW2のスパニングツリーポートプライオリティ4を入力します。
C. SW2でスパニングツリーポートプライオリティ64を入力します。
D. SW1にスパニングツリーポートプライオリティ32を入力します。
Answer: D
Explanation:
Explanation
SW1 needs to block one of its ports to SW2 to avoid a bridging loop between the two switches.
Unfortunately, it blocked the fiber port Link2. But how does SW2 select its blocked port? Well, the answer is based on the BPDUs it receives from SW1. answer 'Enter spanning-tree port-priority 32 on SW1' BPDU is superior than another if it has:
1. answer 'Enter spanning-tree port-priority 32 on SW1' lower Root Bridge ID
2. answer 'Enter spanning-tree port-priority 32 on SW1' lower path cost to the Root
3. answer 'Enter spanning-tree port-priority 32 on SW1' lower Sending Bridge ID
4. answer 'Enter spanning-tree port-priority 32 on SW1' lower Sending Port ID These four parameters are examined in order. In this specific case, all the BPDUs sent by SW1 have the same Root Bridge ID, the same path cost to the Root and the same Sending Bridge ID.
The only parameter left to select the best one is the Sending Port ID (Port ID = port priority + port index). And the port index of Gi0/0 is lower than the port index of Gi0/1 so Link 1 has been chosen as the primary link.
Therefore we must change the port priority to change the primary link. The lower numerical value of port priority, the higher priority that port has. In other words, we must change the port-priority on Gi0/1 of SW1 (not on Gi0/1 of SW2) to a lower value than that of Gi0/0.