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  • Exam Code: AZ-140
  • Exam Name: Configuring and Operating Microsoft Azure Virtual Desktop
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NEW QUESTION: 1
The implementations group has been using the test bed to do a 'proof-of-concept' that requires both Client 1 and Client 2 to access the WEB Server at 209.65.200.241. After several changes to the network addressing, routing scheme, DHCP services, NTP services, and FHRP services, a trouble ticket has been operated indicating that Client 1 cannot ping the 209.65.200.241 address.
Use the supported commands to Isolated the cause of this fault and answer the following questions.
On which device is the fault condition located?
A. ASW2
B. R1
C. ASW1
D. R3
E. R2
F. DSW1
G. R4
H. DSW2
Answer: C
Explanation:
Explanation
Since the Clients are getting an APIPA we know that DHCP is not working. However, upon closer examination of the ASW1 configuration we can see that the problem is not with DHCP, but the fact that the trunks on the port channels are only allowing VLANs 1-9, when the clients belong to VLAN 10. VLAN 10 is not traversing the trunk on ASW1, so the problem is with the trunk configuration on ASW1.
Topic 2, Ticket 2 : ACCESS VLAN
Topology Overview (Actual Troubleshooting lab design is for below network design)
* Client Should have IP 10.2.1.3
* EIGRP 100 is running between switch DSW1 & DSW2
* OSPF (Process ID 1) is running between R1, R2, R3, R4
* Network of OSPF is redistributed in EIGRP
* BGP 65001 is configured on R1 with Webserver cloud AS 65002
* HSRP is running between DSW1 & DSW2 Switches
The company has created the test bed shown in the layer 2 and layer 3 topology exhibits.
This network consists of four routers, two layer 3 switches and two layer 2 switches.
In the IPv4 layer 3 topology, R1, R2, R3, and R4 are running OSPF with an OSPF process number 1.
DSW1, DSW2 and R4 are running EIGRP with an AS of 10. Redistribution is enabled where necessary.
R1 is running a BGP AS with a number of 65001. This AS has an eBGP connection to AS 65002 in the ISP's network. Because the company's address space is in the private range.
R1 is also providing NAT translations between the inside (10.1.0.0/16 & 10.2.0.0/16) networks and outside (209.65.0.0/24) network.
ASW1 and ASW2 are layer 2 switches.
NTP is enabled on all devices with 209.65.200.226 serving as the master clock source.
The client workstations receive their IP address and default gateway via R4's DHCP server.
The default gateway address of 10.2.1.254 is the IP address of HSRP group 10 which is running on DSW1 and DSW2.
In the IPv6 layer 3 topology R1, R2, and R3 are running OSPFv3 with an OSPF process number 6.
DSW1, DSW2 and R4 are running RIPng process name RIP_ZONE.
The two IPv6 routing domains, OSPF 6 and RIPng are connected via GRE tunnel running over the underlying IPv4 OSPF domain. Redistrution is enabled where necessary.
Recently the implementation group has been using the test bed to do a 'proof-of-concept' on several implementations. This involved changing the configuration on one or more of the devices. You will be presented with a series of trouble tickets related to issues introduced during these configurations.
Note: Although trouble tickets have many similar fault indications, each ticket has its own issue and solution.
Each ticket has 3 sub questions that need to be answered & topology remains same.
Question-1 Fault is found on which device,
Question-2 Fault condition is related to,
Question-3 What exact problem is seen & what needs to be done for solution


Client is unable to ping IP 209.65.200.241
Solution
Steps need to follow as below:-
* When we check on client 1 & Client 2 desktop we are not receiving DHCP address from R4 Ipconfig ----- Client will be getting 169.X.X.X
* On ASW1 port Fa1/0/ 1 & Fa1/0/2 access port VLAN 10 was assigned which is using IP address
10.2.1.0/24
Sh run ------- & check for running config of int fa1/0/1 & fa1/0/2

* Here we are not able to see access Vlan10 configured for Port Fa1/0/1 & Fa1/0/2
* Change required: On ASW1, for configuring Access Vlan under interface fa1/0/1 & 1/0/2 we have to enable command switchport access vlan 10

NEW QUESTION: 2
View the Exhibit.

You are designing an IP addressing scheme for the network in the exhibit above.
Each switch represents hosts that reside in separate VLANs. The subnets should be allocated to match the following host capacities:
Router subnet: two hosts

SwitchA subnet: four hosts

SwitchB subnet: 10 hosts

SwitchC subnet: 20 hosts

SwitchD subnet: 50 hosts

You have chosen to subnet the 192.168.51.0/24 network.
Which of the following are you least likely to allocate?
A. a /28 subnet
B. a /26 subnet
C. a /30 subnet
D. a /29 subnet
E. a /25 subnet
F. a /27 subnet
Answer: E
Explanation:
Explanation/Reference:
Section: Addressing and Routing Protocols in an Existing Network Explanation Explanation:
Of the available choices, you are least likely to allocate a /25 subnet. The largest broadcast domain in this scenario contains 50 hosts. A /25 subnet can contain up to 126 assignable hosts. In this scenario, allocating a /25 subnet would reserve half the 192.168.51.0/24 network for a single virtual LAN (VLAN).
The total number of hosts for which you need addresses in this scenario is 86. Therefore, you would only need to use half the /24 subnet if all 86 hosts were residing in the same VLAN.
You should begin allocating address ranges starting with the largest group of hosts to ensure that the entire group has a large, contiguous address range available. Subnetting a contiguous address range in structured, hierarchical fashion enables routers to maintain smaller routing tables and eases administrative burden when troubleshooting.
You are likely to use a /26 subnet. In this scenario, the largest VLAN contains 50 hosts. If you were to divide the 192.168.51.0/25 subnet into two /26 subnets, the result would be two new subnets capable of supporting up to 62 assignable hosts: the 192.168.51.0/26 subnet and the 192.168.51.64/26 subnet.
Therefore, you should start subnetting with a /26 network. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.64/26 subnet to SwitchD's VLAN.
You are likely to use a /27 subnet. The nextlargest broadcast domain in this scenario is the SwitchC subnet, which contains 20 hosts. If you were to divide the 192.168.51.0/26 subnet into two /27 subnets, the result would be two new subnets capable of supporting up to 30 assignable hosts: the 192.168.51.0/27 subnet and the 192.168.51.32/27 subnet. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.32/27 subnet to SwitchC's VLAN.
You are likely to use a /28 subnet. The nextlargest broadcast domain in this scenario is the SwitchB subnet, which contains 10 hosts. If you were to divide the 192.168.51.0/27 subnet into two /28 subnets, the result would be two new subnets capable of supporting up to 14 assignable hosts: the 192.168.51.0/28 subnet and the 192.168.51.16/28 subnet. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.16/28 subnet to SwitchB's VLAN.
You are likely to use a /29 subnet. The nextlargest broadcast domain in this scenario is the SwitchA subnet, which contains four hosts. If you were to divide the 192.168.51.0/28 subnet into two /29 subnets, the result would be two new subnets capable of supporting up to six assignable hosts: the 192.168.51.0/29 subnet and the 192.168.51.8 subnet. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.8/29 subnet to SwitchA's VLAN.
You are likely to use a /30 subnet. The final subnet in this scenario is the link between RouterA and RouterB, which contains two hosts. If you were to divide the 192.168.51.0/29 subnet into two /30 subnets, the result would be two new subnets capable of supporting two assignable hosts each: the
192.168.51.0/30 subnet and the 192.168.51.4/30 subnet. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.4/30 subnet to the link between RouterA and RouterB. This would leave the 192.168.51.0/30 subnet unallocated. However, you could further divide the 192.168.51.0/30 subnet into single /32 host addresses that could then be used for loopback IP addressing on the routers.
Reference:
CCDA 200-310 Official Cert Guide, Chapter 8, IPv4 Address Subnets, pp. 302-310 CCDA 200-310 Official Cert Guide, Chapter 8, Plan for a Hierarchical IP Address Network, pp. 311-312 Cisco: IP Addressing and Subnetting for New Users

NEW QUESTION: 3
You manage a development team that uses the Microsoft Visual Studio Scrum 2.0 process template.
You establish a product backlog, allocate backlog items for a sprint, and define the tasks required to complete the sprint.
You need to ensure that the agreed upon work is assigned to team members.
Who should be responsible for assigning work to team members?
A. Scrum master
B. Team members
C. Team lead
D. Product owner
Answer: B
Explanation:
In Scrum, work should never be directed or assigned. When creating or updating a task, don't assign it to anyone who doesn't request the work.
Professional Scrum Development with Microsoft Visual Studio 2012 p.183

NEW QUESTION: 4
A trade secret:
A. Is a word, name, symbol, color, sound, product shape, or device used to identify goods and to distinguish them from those made or sold by others.
B. Secures and maintains the confidentiality of proprietary technical or business-related information that is adequately protected from disclosure by the owner.
C. Provides the owner with a legally enforceable right to exclude others from practicing the art covered for a specified time period.
D. Protects original works of authorship.
Answer: B
Explanation:
This defines a trade secret.
*Answer "Provides the owner with a legally enforceable right to exclude others from practicing the art covered for a specified time period" refers to a patent.
*Answer "Protects original works of authorship" refers to a copyright.
*Answer "Is a word, name, symbol, color, sound, product shape, or device used to identify goods and to distinguish them from those made or sold by others" refers to a trademark.

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