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D-OME-OE-A-24 Exam Simulator
  • Exam Code: D-OME-OE-A-24
  • Exam Name: Dell OpenManage Operate Achievement
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NEW QUESTION: 1
You work in a company which uses SQL Server 2008. You are the administrator of the company database.
Now you are in charge of a SQL Server 2008 instance.
There is a n On-Line Analytical Processing (OLAP) database named in the instance. The database
contains a dimension table named Clients. Ever hour backup of data of the Clients table is performed. But
the Clinets table contains redundant data. You must keep the disk space used to store the Clients table.
In the options below, which compression technology should you use?
A. You should use windows NTFS file system compression
B. You should use page compression
C. You should use backup compression
D. You should use row compression
Answer: B
Explanation:
Page Compression The second and the most vital compression method is page compression. Page compression allows common data to be shared between rows for a given page. Its uses the following techniques to compress data: Row compression. (Already discussed above) Prefix Compression. For every column in a page duplicate prefixes are identified. These prefixes are saved in compression information headers (CI) which resides after page header. A reference number is assigned to these prefixes and that reference number is replaced where ever those prefixes are being used. Dictionary Compression. Dictionary compression searches for duplicate values through out the page and stores them in CI. The main difference between prefix and dictionary compression is that prefix is only restricted to one column while dictionary is applicable to the complete page. Because of the Prefix Compression and Dictionary Compression, duplicate values are shared between rows in a given page. Which lead us to reduce the disk space used.

NEW QUESTION: 2
Delroy McWilliams, a quantitative analyst with Churn Brothers Brokerage, is examining a data sample and has amassed the following information:
Standard deviation of the sample: 70
Number of observations: 600
Sample mean: 812
Assume that Mr. McWilliams formulates a null hypothesis that states that the value of the population mean is equal to 800. Additionally, assume that the population standard deviation is unknown. Given this information, what is the standard error of the estimate? Further, what is the test statistic? Choose the best answer.
A. 0.014; 857.143
B. 2.858; 11.60
C. None of these answers is completely correct.
D. 0.014; 11.834
E. 8.370; 4.148
F. 8.370; 1.434
G. 2.858; 1.40
Answer: C
Explanation:
Explanation/Reference:
Explanation:
The standard error and test statistic for this example is 2.858 and 4.199, respectively. Therefore, none of these answers is correct.
If the population standard deviation is unknown, as in this example, the standard error of the estimate is found by using the following equation:
{Standard error = s / square root of n} where s = the sample standard deviation and n = the number of observations in the sample.
In this example, all of the necessary information has been provided, and the determination of the standard error of the estimate is found as:
{Standard error = [70 / 24.495] = 2.858}
Now that the standard error of the estimate has been calculated, the test statistic can be found by using the following equation:
{Test statistic = [sample statistic - value of the population parameter under the null hypothesis] / standard error of the sample statistic].
Again, all of the necessary information has been provided, and the calculation of the test statistic is found as follows:
{Test statistic = [812 - 800] / 2.858 = 4.199}

NEW QUESTION: 3
Which two describe a stored procedure? (Choose two.)
A. A stored procedure is a named PL/SQL block that can accept parameters.
B. A stored procedure is typically written in SQL.
C. A stored procedure is a type of PL/SQL subprogram that performs an action.
D. The executable section of a stored procedure contains statements that assign values, control execution, and return values to the calling environment.
E. A stored procedure has three parts: the specification, the body, and the exception handler part .
Answer: A,C

NEW QUESTION: 4
Pace Insurance is a large, multi-line insurance company that also owns several proprietary mutual funds.
The funds are managed individually, but Pace has an investment committee that oversees all of the funds.
This committee is responsible for evaluating the performance of the funds relative to appropriate benchmarks and relative to the stated investment objectives of each individual fund. During a recent investment committee meeting, the poor performance of Pace's equity mutual funds was discussed. In particular, the inability of the portfolio managers to outperform their benchmarks was highlighted. The net conclusion of the committee was to review the performance of the manager responsible for each fund and dismiss those managers whose performance had lagged substantially behind the appropriate benchmark.
The fund with the worst relative performance is the Pace Mid-Cap Fund, which invests in stocks with a capitalization between S40 billion and $80 billion. A review of the operations of the fund found the following:
* The turnover of the fund was almost double that of other similar style mutual funds.
* The fund's portfolio manager solicited input from her entire staff prior to making any decision to sell an existing holding.
* The beta of the Pace Mid-Cap Fund's portfolio was 60% higher than the beta of other similar style mutual funds.
* No stock is considered for purchase in the Mid-Cap Fund unless the portfolio manager has 15 years of financial information on that company, plus independent research reports from at least three different analysts.
* The portfolio manager refuses to increase her technology sector weighting because of past losses the fund incurred in the sector.
* The portfolio manager sold all the fund's energy stocks as the price per barrel of oil rose above $80. She expects oil prices to fall back to the $40 to S50 per barrel range.
A committee member made the following two comments:
Comment 1: "One reason for the poor recent performance of the Mid-Cap Mutual Fund is that the portfolio lacks recognizable companies. I believe that good companies make good investments." Comment 2: "The portfolio manager of the Mid-Cap Mutual Fund refuses to acknowledge her mistakes.
She seems to sell stocks that appreciate, but hold stocks that have declined in value." The supervisor of the Mid-Cap Mutual Fund portfolio manager made the following statements:
Statement 1: "The portfolio manager of the Mid-Cap Mutual Fund has engaged in quarter-end window dressing to make her portfolio look better to investors. The portfolio manager's action is a behavioral trait known as over-reaction." Statement 2: "Each time the portfolio manager of the Mid-Cap Mutual fund trades a stock, she executes the trade by buying or selling one-third of the position at a time, with the trades spread over three months.
The portfolio manager's action is a behavioral trait known as anchoring." Indicate whether Statement 1 and Statement 2 made by the supervisor are correct.
A. Only Statement 1 is correct.
B. Neither Statement is correct.
C. Only Statement 2 is correct.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Statement 1 is incorrect. The behavioral trait is regret minimization, not overreaction. The concept of regret minimization leads to herding behavior. Window dressing is a herding mentality in which portfolio managers show investors that they only invest in stocks that outperform (winners) and avoid poor performing stocks (losers). The overreaction concept asserts that random events can greatly influence an investor's decision making.
Statement 2 is incorrect. The trading described is similar to dollar cost averaging, which is a framing dependence issue that mitigates loss aversion. Anchoring leads to an under-reaction to new information, which does not apply to the portfolio manager's trading strategy. (Study Session 3, LOS 8.a, b)

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