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CTFL-Foundation Exam Simulator
  • Exam Code: CTFL-Foundation
  • Exam Name: ISTQB Certified Tester Foundation Level
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  • Q & A: 40 Questions and Answers
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Weder Bücher noch Zeitschriften lagen herum, Hast du keine Angst?

NEW QUESTION: 1
You need to configure network connectivity between a virtual network named VNET1 and a virtual network named VNET2. The solution must ensure that virtual machines connected to VNET1 can communicate with virtual machines connected to VNET2.
To complete this task, sign in to the Azure portal and modify the Azure resources.
Answer:
Explanation:
See the explanation below.
Explanation
You need to configure VNet Peering between the two networks. The questions states, "The solution must ensure that virtual machines connected to VNET1 can communicate with virtual machines connected to VNET2". It doesn't say the VMs on VNET2 should be able to communicate with VMs on VNET1.
Therefore, we need to configure the peering to allow just the one-way communication.
1. In the Azure portal, type Virtual Networks in the search box, select Virtual Networks from the search results then select VNET1. Alternatively, browse to Virtual Networks in the left navigation pane.
2. In the properties of VNET1, click on Peerings.
3. In the Peerings blade, click Add to add a new peering.
4. In the Name of the peering from VNET1 to remote virtual network box, enter a name such as VNET1-VNET2 (this is the name that the peering will be displayed as in VNET1)
5. In the Virtual Network box, select VNET2.
6. In the Name of the peering from remote virtual network to VNET1 box, enter a name such as VNET2-VNET1 (this is the name that the peering will be displayed as in VNET2).
There is an option Allow virtual network access from VNET to remote virtual network. This should be left as Enabled.
7. For the option Allow virtual network access from remote network to VNET1, click the slider button to Disabled.
8. Click the OK button to save the changes.
Reference:
https://docs.microsoft.com/en-us/azure/virtual-network/virtual-network-manage-peering

NEW QUESTION: 2
You have a computer that runs Windows 7. The computer is a member of an Active Directory domain and has a shared printer. Users report that they can print to the shared printer, but they cannot delete their print jobs.
You need to ensure that users can delete their own print jobs.
What should you do?
A. Stop sharing the local printer and then share it again.
B. Assign the Manage Documents permission to CREATOR OWNER.
C. Restart the Print Spooler service.
D. Assign the Manage Documents permission to SYSTEM.
Answer: B
Explanation:
Manage Documents The user can pause, resume, restart, cancel, and rearrange the order of documents submitted by all other users. The user cannot, however, send documents to the printer or control the status of the printer. By default, the Manage Documents permission is assigned to members of the Creator Owner group. When a user is assigned the Manage Documents permission, the user cannot access existing documents currently waiting to print. The permission will only apply to documents sent to the printer after the permission is assigned to the user.

NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2014 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK()OVER (PARTITION BY CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
Answer: C
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1

NEW QUESTION: 4

A. Option D
B. Option A
C. Option C
D. Option B
Answer: D

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